RSA Encryption Learning

Private Key Generation in RSA Encryption

Step 7 of 9

Learn how to calculate the private key (d) using the modular multiplicative inverse and understand the Extended Euclidean Algorithm.

Understanding the Private Key

The private key (d) is a critical component of RSA encryption that allows the decryption of messages. It is mathematically related to the public exponent (e) and must be kept secret.

Definition: The private key (d) is the modular multiplicative inverse of the public exponent (e) with respect to φ(n). This means that (d × e) mod φ(n) = 1.

Security Importance

The private key must be kept secret as it allows decryption of any message encrypted with the corresponding public key. The security of RSA relies on the difficulty of deriving d from e and n.

Mathematical Relationship

The private key d is calculated using the formula: d ≡ e⁻¹ (mod φ(n)), which means d is the modular multiplicative inverse of e modulo φ(n).

Finding d in RSA

To find the private key d, we need to solve the congruence equation: d⋅e ≡ 1 (mod φ(n)). This means finding a value d such that when multiplied by e and taken modulo φ(n), equals 1.

Example:

Given e = 3 and φ(n) = 40, find d where:

3⋅d ≡ 1 (mod 40)

Testing values systematically:

  • When d = 1: 3⋅1 ≡ 3 (mod 40) ≠ 1
  • When d = 2: 3⋅2 ≡ 6 (mod 40) ≠ 1
  • When d = 3: 3⋅3 ≡ 9 (mod 40) ≠ 1
  • ...
  • When d = 27: 3⋅27 ≡ 1 (mod 40) ✓

Therefore, d = 27 satisfies the congruence equation 3⋅d ≡ 1 (mod 40).

Using the Extended Euclidean Algorithm

Rather than testing values manually, we can efficiently find d using the Extended Euclidean Algorithm. This algorithm helps us solve the congruence equation d⋅e ≡ 1 (mod φ(n)).

Mathematical Foundation:

The congruence equation d⋅e ≡ 1 (mod φ(n)) can be rewritten as:

d⋅e - k⋅φ(n) = 1

where k is some integer. This is exactly what the Extended Euclidean Algorithm solves.

For our example where e = 3 and φ(n) = 40:

1. First, apply the algorithm:

40 = 3 × 13 + 1

2. Working backwards:

1 = 40 - 3 × 13

1 = 40 - 3 × 13

Therefore: d = -13 ≡ 27 (mod 40)

This confirms our earlier result that d = 27 is the solution to 3⋅d ≡ 1 (mod 40).

Extended Euclidean Algorithm Step-by-Step

The Extended Euclidean Algorithm calculates the modular multiplicative inverse through a series of divisions and substitutions.

Algorithm Steps:

  1. Start with φ(n) and e
  2. Apply the Euclidean Algorithm to find gcd(φ(n), e)
  3. Work backwards through the equations to find the coefficients
  4. Extract the coefficient of e, which is the modular multiplicative inverse
  5. Adjust the result if necessary to ensure it's positive

Example with e = 7, φ(n) = 40:

Step 1: Apply the Euclidean Algorithm

40 = 7 × 5 + 5

7 = 5 × 1 + 2

5 = 2 × 2 + 1

2 = 1 × 2 + 0

Step 2: Work backwards

1 = 5 - 2 × 2

1 = 5 - 2 × (7 - 5 × 1)

1 = 5 - 2 × 7 + 2 × 5

1 = 3 × 5 - 2 × 7

1 = 3 × (40 - 7 × 5) - 2 × 7

1 = 3 × 40 - 3 × 7 × 5 - 2 × 7

1 = 3 × 40 - 7 × (3 × 5 + 2)

1 = 3 × 40 - 7 × 17

Therefore, d = -17 ≡ 23 (mod 40)

Interactive Visualization

Enter values in the calculator below to see the Extended Euclidean Algorithm in action

Private Key Calculator Tool

Calculate the private key (d) given the public exponent (e) and φ(n).

Enter values to calculate the private key

Private Key Verification Tool

Verify that your calculated private key (d) works correctly with the public exponent (e).

Practice Exercises

Test your understanding of private key generation in RSA encryption.

Exercise 1: Calculate the Private Key

Given e = 5 and φ(n) = 24, calculate the private key d.

Exercise 2: Verify the Private Key

Check if the following private keys are valid for the given values of e and φ(n).

e = 3, φ(n) = 20, d = 7

e = 11, φ(n) = 60, d = 11

Exercise 3: Complete the Extended Euclidean Algorithm

Fill in the missing values in the Extended Euclidean Algorithm calculation for e = 17 and φ(n) = 60.

60 = 17 × 3 + 9

17 = 9 × 1 + 8

9 = 8 × 1 + 1

8 = 1 × 8 + 0

Working backwards:

1 = 9 - 8 × 1

1 = 9 - (17 - 9 × 1) × 1

1 = 9 - 17 + 9 = 2 × 9 - 17

1 = 2 × (60 - 17 × 3) - 17

1 = 2 × 60 - 2 × 17 × 3 - 17

1 = 2 × 60 - 17 × (2 × 3 + 1)

1 = 2 × 60 - 17 ×

Knowledge Check

1. What is the mathematical relationship between the private key (d) and the public exponent (e)?

2. Which algorithm is commonly used to calculate the modular multiplicative inverse?

3. Why must the private key be kept secret in RSA encryption?